# std::chrono::year_month_day_last::year, std::chrono::year_month_day_last::month, std::chrono::year_month_day_last::day, std::chrono::year_month_day_last::month_day_last

From cppreference.com
< cpp‎ | chrono‎ | year month day last

constexpr std::chrono::year year() const noexcept; | (1) | (since C++20)
constexpr std::chrono::month month() const noexcept; | (2) | (since C++20)
constexpr std::chrono::day day() const noexcept; | (3) | (since C++20)
constexpr std::chrono::month_day_last month_day_last() const noexcept; | (4) | (since C++20)

Retrieves the field values stored in this `year_month_day_last` object.

### Return values

1) Returns the stored std::chrono::year value.
2) Returns the stored std::chrono::month value.
3) A std::chrono::day value corresponding to the last day of the stored year and month. If this->ok() is false, the return value is unspecified.
4) A std::chrono::month_day_last constructed from `month()`.

### Example

Run this code

    #include <iostream>
    #include <chrono>

    int main()
    {
        std::cout << std::boolalpha;

        constexpr auto ymdl {std::chrono::last/11/2020};
        std::cout << (ymdl.day() == std::chrono::day(30)) << ' '
                  << (ymdl.month() == std::chrono::November) << ' '
                  << (ymdl.year() == std::chrono::year(2020)) << ' ';
        constexpr auto mdl = ymdl.month_day_last();
        std::cout << (mdl == (std::chrono::November/std::chrono::last)) << '\n';
    }

Output:

    true true true true

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