# std::chrono::year_month_weekday_last::operator sys_days, std::chrono::year_month_weekday_last::operator local_days

From cppreference.com
< cpp‎ | chrono‎ | year month weekday last

constexpr operator std::chrono::sys_days() const noexcept; | (1) | (since C++20)
constexpr explicit operator std::chrono::local_days() const noexcept; | (2) | (since C++20)

Converts `*this` to a std::chrono::time_point representing the same date as this `year_month_weekday_last`.

1) If ok() is true, returns a `sys_days` that represents the last weekday() of the year() and month(). Otherwise, the returned value is unspecified.
2) Same as (1), but returns `local_days` instead of `sys_days`. Equivalent to local_days(sys_days(*this).time_since_epoch()).

### Example

Run this code

    #include <iostream>
    #include <chrono>
    using namespace std::chrono;

    int main()
    {
        std::cout << std::boolalpha;

        constexpr auto ymwdl {Tuesday[last]/11/2021};
        static_assert(static_cast<local_days>(ymwdl) ==
                      static_cast<local_days>(November/30/2021));
        // convert from field-based to serial-based to add days
        constexpr auto sd = static_cast<sys_days>(ymwdl);
        constexpr year_month_day ymd {sd + days(10)};
        std::cout << (ymd == December/10/2021) << '\n';
    }

Output:

    true

Retrieved from "https://en.cppreference.com/mwiki/index.php?title=cpp/chrono/year_month_weekday_last/operator_days&oldid=154477"