# std::ranges::borrowed_range, std::ranges::enable_borrowed_range

From cppreference.com
< cpp‎ | ranges

Defined in header `<ranges>` |  |
template<class R> concept borrowed_range = ranges::range<R> && (std::is_lvalue_reference_v<R> || ranges::enable_borrowed_range<std::remove_cvref_t<R>>); | (1) | (since C++20)
template<class R> inline constexpr bool enable_borrowed_range = false; | (2) | (since C++20)

1) The concept `borrowed_range` defines the requirements of a range such that a function can take it by value and return iterators obtained from it without danger of dangling.
2) The `enable_borrowed_range` variable template is used to indicate whether a `range` is a `borrowed_range`. The primary template is defined as false.

### Semantic requirements

Let `U` be std::remove_reference_t<T> if `T` is an rvalue reference type, and `T` otherwise. Given a variable `u` of type `U`, `T` models `borrowed_range` only if the validity of iterators obtained from `u` is not tied to the lifetime of that variable.

### Specializations

Specializations of `enable_borrowed_range` for all specializations of the following standard templates are defined as true:

- `std::basic_string_view`
- `std::span`
- `std::ranges::subrange`
- `std::ranges::ref_view`
- `std::ranges::empty_view`
- `std::ranges::iota_view`

Specialization of `enable_borrowed_range` for the following standard range adaptors are defined as true if and only if std::ranges::enable_borrowed_range<V> is true, where `V` is the underlying view type:

- `std::ranges::owning_view`
- `std::ranges::take_view`
- `std::ranges::drop_view`
- `std::ranges::drop_while_view`
- `std::ranges::common_view`
- `std::ranges::reverse_view`
- `std::ranges::elements_view`

`std::ranges::adjacent_view` | (since C++23)

Specialization for `std::ranges::zip_view` is defined as true if and only if (std::ranges::enable_borrowed_range<Vs> && ...) is true, where `Vs...` are all view types it adapts. | (since C++23)

Users may specialize `enable_borrowed_range` to true for cv-unqualified program-defined types which model `borrowed_range`, and false for types which do not. Such specializations shall be usable in constant expressions and have type const bool.

### Example

Demonstrates the specializations of `enable_borrowed_range` for program defined types. Such specializations protect against potentially dangling results.

Run this code

    #include <algorithm>
    #include <array>
    #include <cstddef>
    #include <iostream>
    #include <ranges>
    #include <span>
    #include <type_traits>

    template <typename T, std::size_t N>
    struct MyRange : std::array<T, N> { };

    template <typename T, std::size_t N>
    inline constexpr bool std::ranges::enable_borrowed_range<MyRange<T, N>> = false;

    template <typename T, std::size_t N>
    struct MyBorrowedRange : std::span<T, N> { };

    template <typename T, std::size_t N>
    inline constexpr bool std::ranges::enable_borrowed_range<MyBorrowedRange<T, N>> = true;

    int main()
    {
        static_assert(std::ranges::range<MyRange<int, 8>>);
        static_assert(std::ranges::borrowed_range<MyRange<int, 8>> == false);
        static_assert(std::ranges::range<MyBorrowedRange<int, 8>>);
        static_assert(std::ranges::borrowed_range<MyBorrowedRange<int, 8>> == true);

        auto getMyRangeByValue = [] { return MyRange<int, 4>{ {1, 2, 42, 3} }; };
        auto dangling_iter = std::ranges::max_element(getMyRangeByValue());
        static_assert(std::is_same_v<std::ranges::dangling, decltype(dangling_iter)>);
    //  *dangling_iter; // compilation error (i.e. dangling protection works.)

        auto my = MyRange<int, 4>{ {1, 2, 42, 3} };
        auto valid_iter = std::ranges::max_element(my);
        std::cout << *valid_iter << ' '; // OK: 42

        auto getMyBorrowedRangeByValue = [] {
            static int sa[4] {1, 2, 42, 3};
            return MyBorrowedRange<int, std::size(sa)>{sa};
        };
        auto valid_iter2 = std::ranges::max_element(getMyBorrowedRangeByValue());
        std::cout << *valid_iter2 << '\n'; // OK: 42
    }

Output:

    42 42

### See also

ranges::dangling (C++20) | a placeholder type indicating that an iterator or a `subrange` should not be returned since it would be dangling (class)

Retrieved from "https://en.cppreference.com/mwiki/index.php?title=cpp/ranges/borrowed_range&oldid=137457"