# std::chrono::year::operator++, std::chrono::year::operator--

From cppreference.com
< cpp‎ | chrono‎ | year

constexpr std::chrono::year& operator++() noexcept; | (1) | (since C++20)
constexpr std::chrono::year operator++(int) noexcept; | (2) | (since C++20)
constexpr std::chrono::year& operator--() noexcept; | (3) | (since C++20)
constexpr std::chrono::year operator--(int) noexcept; | (4) | (since C++20)

Adds or subtracts 1 from the year value.

1-2) Performs *this += std::chrono::years{1};
3-4) Performs *this -= std::chrono::years{1};

### Parameters

(none)

### Return value

1,3) a reference to this `year` after modification
2,4) a copy of the `year` made before modification

### Notes

If the result would be outside the range [-32767, 32767], the actual stored value is unspecified.

### Example

Run this code

    #include <iostream>
    #include <chrono>

    int main()
    {
        std::cout << std::boolalpha;

        std::chrono::year y {2020};
        std::cout << (++y == std::chrono::year(2021)) << ' ';
        std::cout << (--y == std::chrono::year(2020)) << '\n';

        using namespace std::literals::chrono_literals;
        y = 32767y;
        y++; //< unspecified, see Notes
        std::cout << static_cast<int>(y) << '\n';
    }

Possible output:

    true true
    -32768

### See also

operator+=operator-= | adds or subtracts a number of years from a `year` (public member function)
operator+operator- (C++20) | performs arithmetic on `year`s (function)

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